Water Resources and Environmental Hydraulics · Environmental Hydraulics · 2 marks · Numerical answer
A 314 kN plunger balances oil of specific gravity.9 in a 1.5 m diameter vessel. A 1.5 cm tube connects to a pressure gauge at 1.5 m above the plunger/oil interface;other heights are shown. Find gauge pressure in kPa, to two decimals.
Pressure immediately below the plunger is $p_0=W/A=314/[\pi(1.5)^2/4]=177.68765$ kPa. The gauge is 1.5 m higher, so hydrostatic pressure decreases by $\rho g\Delta z=900(9.81)(1.5)/1000=13.2435$ kPa. Thus gauge reading is **164.44 kPa**. Connecting-tube diameter and the downward then upward path do not affect the net elevation correction.
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