Home › Previous year questions › GATE 2015 CS (CS2) › Question 7GATE 2015 CS (CS2) – Question 7 General Aptitude · Quantitative Aptitude: Data Interpretation, Arithmetic and Number Computation · 2 marks · Multiple choice
In triangle PQR, PQ=r, PR=q and QR=p. PS bisects ∠QPR, S lies on QR, and ∠QPS=60°. Find PS.
$(q+r)/(qr)$ $qr/(q+r)$ $\sqrt{q^2+r^2}$ $(q+r)^2/(qr)$ Practise this question in The GATE Grind →
Show answer and explanation Correct answer: (B) $qr/(q+r)$
Explanation The angle at P is 120°. Write the triangle area as the sum of areas PQS and PRS: $\frac12 qr\sin120^\circ=\frac12(r+q)PS\sin60^\circ$. The sine values are equal, hence PS=qr/(q+r), B.
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