Biomaterials and Tissue Engineering · Biomaterial Properties · 1 mark · Numerical answer
A hollow spherical nanoparticle has outer radius 5 nm and uniform shell thickness 3 nm. Find shell volume divided by hollow-core volume, to one decimal place.
Inner radius is 5−3=2 nm. Shell volume is (4π/3)(5³−2³), while core volume is (4π/3)2³. The common factor cancels, giving (125−8)/8=117/8=14.625. Rounded to one decimal place this is 14.6.
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