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GATE 2026 BM – Question 43

Sensors and Bioinstrumentation · Biopotentials and Electrodes · 2 marks · Multiple choice

An EEG PSD has band-average values (μV²/Hz): 0.4–4 Hz:3; 4–8:4; 8–13:8; 13–30:5; 30–100:3. The noise floor is 2 μV²/Hz. Find the alpha-band SNR in dB using the source’s band-PSD/noise-floor convention.

  1. 1.76
  2. 3.01
  3. 6.02
  4. 3.98

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Correct answer: (C) 6.02

Explanation

The alpha band is eight to thirteen hertz and its quoted PSD is eight. Dividing by the noise floor two gives power ratio four; common bandwidth cancels. Therefore SNR=10 log₁₀4≈6.02 dB, C. This is the published convention using the quoted band PSD directly, rather than first subtracting the noise floor.

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