The nonzero input samples are x[1]=.1,x[2]=.5,x[3]=.4; h is supported at zero and one. Thus y[2]=.5h[0]+.1h[1]=1 and y[3]=.4h[0]+.5h[1]=0. The second equation gives h[1]=−.8h[0]. Substitution yields .42h[0]=1, so h[0]=2.38095, D.
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