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GATE 2017 EC (EC2) – Question 21

Analog Circuits · BJT and MOSFET Amplifiers · 1 mark · Numerical answer

Consider an n-channel MOSFET of width $W$, length $L$, channel electron mobility $\mu_n$ and oxide capacitance per unit area $C_{ox}$. Given $V_{GS}=0.7$ V, $V_{DS}=0.1$ V, $\mu_nC_{ox}=100\ \mathrm{\mu A/V^2}$, $V_{TH}=0.3$ V and $W/L=50$, the transconductance $g_m$ (in mA/V) is ________.

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Correct answer: 0.45 to 0.55

Explanation

First identify the region: $V_{GS}-V_{TH}=0.4$ V, larger than $V_{DS}=0.1$ V. The device is in the linear region, not saturation.

The linear-region current is $I_D=\mu_nC_{ox}(W/L)[(V_{GS}-V_{TH})V_{DS}-V_{DS}^2/2]$. Differentiate with respect to $V_{GS}$ at fixed $V_{DS}$ to get $g_m=\mu_nC_{ox}(W/L)V_{DS}$.

Thus $g_m=100(50)(0.1)=500$ μA/V, or **0.50 mA/V**.

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