Analog Circuits · Diode Circuits · 1 mark · Numerical answer
The output $V_o$ of the diode circuit shown is connected to an averaging DC voltmeter. The input is $10\sin\omega t$ V at 50 Hz. Neglecting the voltage drop across the diode, the DC voltmeter reading (in volts) is ________.
The diode conducts on the positive half-cycle and blocks the negative half-cycle. Thus the output is a half-wave rectified sine with peak 10 V.
The average over a complete cycle is $$V_{DC}=\frac1{2\pi}\int_0^\pi10\sin\theta\,d\theta=\frac{10}{\pi}.$$ This is **3.1831 V**, within the official interval 3.15–3.21 V. A DC averaging meter reads this mean, rather than the rms value.
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