GATE 2016 EC (EC2) – Question 5
S, M, E and F work shifts on a project. M works at twice the efficiency of the others but for half as many days as E. S and M have 6-hour daily shifts; E and F have 12-hour shifts. The ratio of M’s contribution to E’s is
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Correct answer: (B) 1:2
Explanation
Work equals hourly efficiency multiplied by hours per day and days. Let E's efficiency be r and E's days be d. Then E contributes 12rd.
M has efficiency 2r, daily hours 6 and days d/2, contributing $2r\cdot6\cdot d/2=6rd$. Hence M:E=6:12=**1:2, B**.
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