GATE 2021 EC – Question 17
The energy band diagram of a p-type semiconductor bar of length $L$ under equilibrium condition (i.e., the Fermi energy level $E_F$ is constant) is shown in the figure. The valance band $E_V$ is sloped since doping is non-uniform along the bar. The difference between the valance band at the two edges of the bar is $\Delta$.
If the charge of an electron is $q$, then the magnitude of the electric field developed inside this semiconductor bar is

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Correct answer: (A) $\frac{\Delta}{qL}$
Explanation
The electric field is the slope of the band edge divided by the electron charge, $E=\frac1q\frac{dE_V}{dx}$. The band edge changes linearly by $\Delta$ over the length $L$, so $|E|=\frac{\Delta}{qL}$.