The 1 F capacitor in the circuit is initially uncharged. The energy transferred from the 10 V DC source until steady state, in joules to one decimal place, is ________.
The symmetric resistor bridge provides a finite path from the capacitor's right plate to ground; its middle resistor has no voltage across it. At final DC steady state no current flows, so the right plate is at ground and the capacitor voltage is 10 V.
Charge supplied by the source is ΔQ=CV=1×10=10 C. Source energy is $V\Delta Q=10(10)=$ **100.0 J**. Half remains in the capacitor; half is dissipated in resistors, so using only stored energy would undercount the source transfer.
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