GATE 2016 EE (EE2) – Question 33
The voltage and current sources in the circuit are ideal. The output voltage across the current source, in volts, is

Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (D) 20
Explanation
The 5 A source injects current into the upper output node. That current must flow leftward through the 2 Ω resistor to the 10 V source.
The output node is consequently 5×2=10 V above the voltage source's upper terminal. Thus Vout=10+10=**20 V, D**, with the marked positive polarity.
More Network solution methods: KCL, KVL, Node and Mesh analysis questions
- GATE 2016 EE (EE2) Q34
- GATE 2016 EE (EE2) Q44
- GATE 2015 EE (EE2) Q29
- GATE 2024 EE Q12
- GATE 2024 EE Q13
- GATE 2024 EE Q48
All Network solution methods: KCL, KVL, Node and Mesh analysis questions →