GATE 2016 EE (EE2) – Question 44

For the circuit shown, the driving-point impedance seen by source Vs in ohms is ________.

Show answer and explanation

Correct answer: 19.5 to 20.5

Explanation

Let source current be Is and the voltage across the left 2 Ω resistor be V1=2Is. The dependent source injects 4V1=8Is into the next node.

The total current leaving that node through its passive load is 9Is. Its equivalent resistance to ground is 3||(2+4)=2 Ω, so its voltage is 18Is.

Source voltage adds the initial resistor drop: Vs=18Is+2Is=20Is. Therefore **Zin=20 Ω**.

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