The readings satisfy W1+W2=P=5 kW and tanφ=√3(W1−W2)/(W1+W2). With cosφ≈0.707, φ≈45° and tanφ≈1.
Thus W1−W2≈5/√3=2.88675 kW. Adding and subtracting gives W1≈3.9434 and W2≈1.0566 kW. Hence **A**; exchanging instrument labels swaps the pair without changing the answer.
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