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GATE 2015 EE (EE2) – Question 46

Electromagnetic Fields · Coulomb's Law, Electric Field Intensity, Electric Flux Density, Gauss's Law, Divergence · 2 marks · Multiple choice

Two grounded perpendicular semi-infinite conducting sheets are shown. Charge +Q is distance d from both. Its force is $[Q^2/(4\pi\epsilon_0d^2)]\mathbf K$. Find K.

Diagram for GATE 2015 EE (EE2) question 46
  1. $0$
  2. $-\hat i/4-\hat j/4$
  3. $-\hat i/8-\hat j/8$
  4. $[(1-2\sqrt2)/(8\sqrt2)](\hat i+\hat j)$

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Correct answer: (D) $[(1-2\sqrt2)/(8\sqrt2)](\hat i+\hat j)$

Explanation

Put +Q at (d,d). The image construction has −Q at (−d,d), −Q at (d,−d), and +Q at (−d,−d).

In the stated force units, the two negative images contribute −i/4 and −j/4. The diagonal positive image is 2√2d away, giving magnitude 1/8 and each component 1/(8√2).

Each net component is −1/4+1/(8√2)=(1−2√2)/(8√2). Thus **D**.

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