Mining Methods and Machinery · Mining Machinery · 2 marks · Numerical answer
Direct-rope haulage produces24 tonnes/hour over610 m at gradient1 in12. Cars carry1 tonne payload and have0.5 tonne tare. Rope speed is1.694 m/s and changeover takes3 min. With g=10 m/s²,ignore friction and rope mass. Find minimum lifting power in kW to three decimals.
Round-trip travel is2×610/1.694≈720.19 s; add180 s changeover for about15 min per trip. At24 tonnes/hour,each trip must carry6 tonnes,requiring six cars. Loaded mass is6×1.5=9 tonnes. Using sinθ≈1/12,the raising force is9000×10/12=7500 N. Power=7500×1.694=12.705 kW. The slight cycle rounding follows the given nominal speed.
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