Mining Methods and Machinery · Mining Machinery · 2 marks · Numerical answer
A 35 kW motor drives a 600 mm pulley at 400 rpm. Belt tensions satisfy Ttight=2.5Tslack. Maximum tension is 8 N per mm belt width. Find minimum belt width in mm, to two decimals.
Belt speed isπ×0.6×400/60=12.566 m/s. Tension difference is 35000/v≈2785.21 N. With ratio 2.5, the tight tension is(2.5/1.5)×2785.21≈4642.02 N. Divide by 8 N/mm to obtain 580.25 mm. This neglects losses and any separate centrifugal-tension correction as specified.
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