Mining Methods and Machinery · Mining Machinery · 2 marks · Numerical answer
Twelve detonators are in series. Each has resistance 1.48 Ω and 1.5 m lead wire of 0.04 Ω/m. The blasting cable is 120 m long and each conductor has 0.009 Ω/m. Find circuit resistance in Ω, to two decimals.
Detonator resistance totals 12×1.48=17.76 Ω. Each lead pair contributes 2×1.5×0.04=0.12 Ω, or 1.44 Ω over twelve. The two cable conductors contribute 2×120×0.009=2.16 Ω. Total 17.76+1.44+2.16=21.36 Ω. The return conductors must be counted.
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