Mining Methods and Machinery · Mining Machinery · 2 marks · Numerical answer
A thermal station burns 7000 tonnes/day of coal of calorific value 4000 kcal/kg. Thermal efficiency is 40%, electrical efficiency 85%, and 860 kcal equals 1 kWh. Find generation per day in MWh, to one decimal.
Daily heat input is 7, 000, 000×4000 kcal. Apply both efficiencies: useful electrical equivalent is this input×0.40×0.85. Divide by 860 for kWh and then by 1000 for MWh. Result is 11069.7674 MWh/day, or 11069.8 MWh/day. The two efficiencies multiply rather than add.
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