Mining Methods and Machinery · Mining Machinery · 1 mark · Numerical answer
A circular track has radius 300 m and maximum elevation difference 0.1 m across 1.6 m width. Neglecting side friction, find balancing vehicle speed in m/s to two decimals.
For the banked-track balance, v²/(gR)=tanθ≈e/b=0.1/1.6. Thus v=√(9.81×300×0.1/1.6)=13.56 m/s. This is the ideal balance-speed interpretation intended; actual overturning limits would additionally require centre-of-mass geometry.
More Mining Machinery questions
GATE 2024 MN Q51– A pump raises 320 m³/hour through 180 m head at overall efficiency 0.70. Mine-water unit…
GATE 2024 MN Q62– A 35 kW motor drives a 600 mm pulley at 400 rpm. Belt tensions satisfy Ttight=2.5Tslack.…
GATE 2024 MN Q63– Replace a winding rope in the shown 1.2 m drum/sheave system. Shaft depth 215 m, headgear…
GATE 2024 MN Q65– Twelve detonators are in series. Each has resistance 1.48 Ω and 1.5 m lead wire of 0.04…
GATE 2023 MN Q56– A thermal station burns 7000 tonnes/day of coal of calorific value 4000 kcal/kg. Thermal…
GATE 2023 MN Q65– A water turbine pump has backward-curved impellers of diameter 35 cm running at 1200 rpm.…