GATE 2017 EE – Question 53
In the circuit shown below, the maximum power transferred to the resistor R is ________ W.

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Correct answer: 3 to 3.1
Explanation
Remove R and find the Thevenin equivalent at its terminals. The 6 V source makes the second node 6 V above the first. Applying KCL to the combined node, the current from the 5 V source is $\frac{5 - V_1}{5}$, and the current leaving is $\frac{V_1 + 6}{5} + 2$. Setting them equal gives $5 - V_1 = V_1 + 6 + 10$, so $V_{oc} = V_1 = -5.5$ V. With the sources off, the resistance seen at R is the two $5\ \Omega$ resistors in parallel, $R_{th} = 2.5\ \Omega$. The maximum power is $\frac{V_{oc}^2}{4R_{th}} = \frac{30.25}{10} = 3.025$ W.