GATE 2018 ME (ME2) – Question 42
A cam follower rises by h while the cam rotates through δ radians at constant angular velocity ω. The follower accelerates uniformly for the first half of the rise and decelerates uniformly for the second half, with equal magnitudes. Find maximum follower velocity.
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Correct answer: (C) $2h\omega/\delta$
Explanation
The rise lasts $t_r=\delta/\omega$. Equal acceleration and deceleration produce a triangular velocity–time graph. Its area is displacement: $h=\tfrac12t_rv_{\max}$. Thus $v_{\max}=2h\omega/\delta$: **C**.