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GATE 2016 CE (CE1) – Question 43

Structural Analysis · Deflections of determinate beams, frames and trusses · 2 marks · Multiple choice

A plane truss with applied loads is shown in the figure. The members which do not carry any force are

Diagram for GATE 2016 CE (CE1) question 43
  1. FT, TG, HU, MP, PL
  2. ET, GS, UR, VR, QL
  3. FT, GS, HU, MP, QL
  4. MP, PL, HU, FT, UR

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Show answer and explanation

Correct answer: (A) FT, TG, HU, MP, PL

Explanation

At an unloaded joint with two collinear members, the third non-collinear member carries zero force. Apply this at F,M and H to obtain FT=MP=HU=0. With FT removed, equilibrium at T also gives TG=0; with MP removed, equilibrium at P gives PL=0. The complete listed set is **FT,TG,HU,MP,PL, A**.