GATE 2014 CS (CS1) – Question 37
A TCP connection has congestion window 32 KB when timeout occurs. RTT is 100 ms and MSS is 2 KB. Find time to recover a 32 KB congestion window (ms).
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Correct answer: 1100 to 1300
Explanation
A32KB window with2KB MSS contains16segments. After timeout, take cwnd=1MSS and ssthresh=8MSS. Slow start reaches2,4,8 over three RTTs; additive increase then requires eight RTTs to reach16. Total11RTTs×100ms=**1100ms**. Update-boundary conventions motivate the official1100–1300 interval.