GATE 2014 CS (CS1) – Question 38
Selective-repeat sliding-window frames are 1 KB over a 1.5 Mbps link with one-way latency 50 ms. For link utilization 60%, find minimum sequence-number field size (bits).
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Correct answer: 5 to 5
Explanation
A1KB frame takes approximately5.33ms using1000bytes, while round-trip propagation is100ms. Utilisation W/(1+2a)≥0.6 requires W≥12frames(also12using1024bytes). Selective repeat needs a sequence space at least2W=24. Therefore ceil(log₂24)=**5bits**.