GATE 2014 EC (EC1) – Question 18
A photodiode receives optical power 10 µW and has responsivity 0.8 A/W. Find generated photocurrent (µA).
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Show answer and explanation
Correct answer: 7.99 to 8.01
Explanation
Photodiode responsivity is generated current divided by incident optical power. Thus I=0.8A/W×10µW=8×10⁻⁶A=**8µA**. Convert the optical power to watts before multiplication; the quoted responsivity already includes the device conversion efficiency.