GATE 2014 EC (EC4) – Question 50
Find Y implemented by the 8-to-1 multiplexer shown.

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Correct answer: (C) $AB\overline C+\overline ACD$
Explanation
Selectors are A,B,C. Inputs I1and I3equal D, contributing ĀB̄CD+ĀBCD=ĀCD. Input I6is1, contributing ABC̄; all other inputs are0. Therefore **Y=ABC̄+ĀCD,C**. D is a data variable, not one of the three select bits.