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GATE 2026 PI – Question 61

Engineering Mathematics · Probability and Statistics · 2 marks · Numerical answer

Soldering-defect count per semiconductor device is Poisson with $p(x)=e^{-\lambda}\lambda^x/x!$ and mean three. Find the probability a randomly chosen device has at least two defects (two decimals).

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Correct answer: 0.78 to 0.82

Explanation

Here λ = 3. By complementation, $P(X\ge2)=1-P(0)-P(1)=1-e^{-3}-3e^{-3}=1-4e^{-3}\approx0.800852$. Rounded answer: **0.80**.

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