The position vector B→A is (0.1,0.2) m. The force points up and left, making 60° above −X, so $F_x=-500$ N and $F_y=866.025$ N. Thus $M_B=r_xF_y-r_yF_x=0.1(866.025)-0.2(-500)=186.603$ N·m. Magnitude is **186.6 N·m**.
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