GATE 2021 PI – Question 56

Manufacturing Processes II · Machining · 2 marks · Numerical answer

Orthogonal machining of mild steel uses rake 15°, uncut chip thickness 0.9 mm and chip thickness 1.8 mm. Find shear angle in degrees to one decimal.

Show answer and explanation

Correct answer: 28.0 to 30.0

Explanation

Chip ratio is r = 0.9/1.8 = 0.5. $\tan\phi=r\cos\alpha/(1-r\sin\alpha)=0.5\cos15^\circ/(1-0.5\sin15^\circ)$. This gives **φ ≈ 29.0°**.

GATE 2026 PI Q33 – The modified Taylor law is VTnfm=constant, where speed V is m/s, life T is minutes, feed f…
GATE 2026 PI Q47 – The source prints the minimum-energy orthogonal-machining relation =C-/2+/2, with φ shear…
GATE 2026 PI Q51 – Which ONE OR MORE work materials are NOT commonly machined with diamond cutting tools?
GATE 2025 PI Q22 – An 8 mm through-hole is needed in 30 mm mild-steel plate. Which process best combines high…
GATE 2025 PI Q30 – In orthogonal straight turning, feed is 0.1 mm/rev and cut depth is 0.5 mm. ASA side…
GATE 2025 PI Q39 – Match grinding terms P: loading; Q: glazing; R: dressing; S: truing, with definitions 1:…