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GATE 2020 PI – Question 57

Manufacturing Processes II · Machining · 2 marks · Numerical answer

Taylor’s tool-life exponent is n=0.5. If cutting speed is halved with all other conditions unchanged, find percentage increase in tool life.

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Correct answer: 300 to 300

Explanation

VTⁿ=C gives T₂/T₁=(V₁/V₂)^(1/n)=2²=4. New life is400% of the old value, so its increase is(4−1)×100=300%. Distinguish the new percentage from the percentage gain.

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