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GATE 2026 AG – Question 45

Agricultural Process Engineering · Evaporation and Drying · 2 marks · Multiple choice

A single-effect evaporator concentrates orange juice so product solids concentration/feed solids concentration=2.7. Feed is 100 kg/h at 30°C, and evaporation is at 60°C. Juice specific heat is 3.9 kJ/(kg·°C) and latent heat at 60°C is 2450 kJ/kg. Find the nearest total heat requirement in MJ/h.

  1. 165.96
  2. 117.06
  3. 154.26
  4. 142.56

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Correct answer: (A) 165.96

Explanation

Conserve solids:$Fx_f=Px_p$,and $x_p=2.7x_f$,so product flow $P=100/2.7=37.037$ kg/h. Water evaporated is $V=100-P=62.963$ kg/h. Sensible duty is $100(3.9)(60-30)=11700$ kJ/h, and latent duty is $62.963(2450)=154259.26$ kJ/h. Total is 165959.26 kJ/h=**165.96 MJ/h, A**.

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