Gas A has aqueous solubility16 mg/L at vapor pressure.042 atm and 25°C. In a closed system its gas concentration is 10⁻³ mol/L. Use ideal R=.0821 L·atm/(mol·K). Find aqueous concentration in mg/L, to two decimals.
Assuming Henry’s law is linear at this temperature, the reference solubility gives $C_w/p=16/.042$. Gas-phase partial pressure is $p=C_gRT=.001(.0821)(298)=.0244658$ atm. Therefore $C_w=16(.0244658)/.042=\mathbf{9.32}$ mg/L.
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