GATE 2025 BM – Question 55

Electrical Circuits · AC Circuits and Resonance · 2 marks · Numerical answer

A series RLC circuit has Vrms=240 V,R=60 Ω,L=10 mH,C=8 μF. Find RMS current at resonance, nearest integer amperes.

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Correct answer: 4 to 4

Explanation

At series resonance, inductive and capacitive reactances cancel, leaving impedance equal to the resistance sixty ohms. Hence Irms=Vrms/R=240/60=4 A. No √2 conversion is needed because both given voltage and requested current are RMS.

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