An analog signal sampled at 100 MHz produces 1024 samples. Only those samples are used for a 1024-point FFT. Find adjacent frequency-bin separation in kHz.
FFT frequency spacing is fs/N. Substituting gives 100×10⁶/1024=97656.25 Hz=97.65625 kHz. Rounded to two decimals this is 97.66 kHz, B. Sample frequency itself is not the frequency resolution.
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