The right-hand divider is loaded by its 2R connection to virtual ground; its midpoint is Vout/2. The right inverter has gain −R/(2R), giving −Vout/4, and the bottom unity inverter produces +Vout/4. At the top inverting input, voltage equals Vin. KCL gives Vin/R+(Vin−Vout)/(4R)+(Vin−Vout/4)/(4R)=0. Thus (3/2)Vin=(5/16)Vout and gain=24/5=4.80, C.
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