GATE 2020 BM – Question 41
Find the nearest power dissipated in the 3 Ω resistor of the shown circuit, with 2 A current source, 2 V voltage source and resistors 2 Ω,2 Ω,4 Ω,3 Ω.
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Correct answer: (A) 3 W
Explanation
The two left two-ohm resistors are in series, equivalent to four ohms from the top node to ground. Let top voltage be V. The other four-ohm branch terminates at +2 V. KCL gives V/4+(V−2)/4+V/3=2. Multiplying by twelve yields 10V−6=24, so V=3 V. Power in three ohms is V²/3=3 W, A.