Find the magnitude of current gain Iload/Iin in the shown dependent-source circuit, to two decimal places. Input resistors are 5 kΩ and 1 kΩ; the output source is 100I_b with 10 kΩ in parallel with the 1 kΩ load.
Input current division gives I_b/Iin=5/(5+1)=5/6. The output controlled source has magnitude 100I_b; its current divides between ten-kilohm and one-kilohm branches. The load receives fraction 10/(10+1)=10/11, with sign opposite the source arrow. Thus gain magnitude=100×(5/6)×(10/11)=75.7576, or 75.76.
More Network Theorems questions
GATE 2021 BM Q13– Three resistors are connected to ideal sources as shown: current source 1.2 A, voltage…
GATE 2021 BM Q39– In the shown bridge, Vₛ=100 V, R₁=30 Ω,R₂=60 Ω,R₃=90 Ω,R₄=45 Ω,R₅=30 Ω. Find current…
GATE 2020 BM Q41– Find the nearest power dissipated in the 3 Ω resistor of the shown circuit, with 2 A…
GATE 2026 BM Q29– Find the Thevenin voltage in volts at the RLoad terminals of the shown 15 V, three-100 Ω…
GATE 2024 BM Q46– In the shown source network, a 5 V source in series with 1 Ω is parallel to an upward 1 A…
GATE 2024 BM Q57– Find the equivalent impedance ZAB of the shown network, in ohms to one decimal place. Each…
