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GATE 2017 EC (EC2) – Question 25

Digital Circuits · Combinatorial Circuits · 1 mark · MTA

For the circuit shown, P and Q are the inputs and Y is the output. The logic implemented by the circuit is

Diagram for GATE 2017 EC (EC2) question 25
  1. XNOR
  2. XOR
  3. NOR
  4. OR

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Show answer and explanation

Correct answer: MTA

Explanation

**Official disposition: marks to all (MTA).** No single option is required for grading.

If the MOS devices are treated as ideal controlled switches, P=0 connects Y through the PMOS to Q, while P=1 connects it through the NMOS to the inverted Q signal. That ideal switch table suggests XNOR.

However, the shown devices use signal-dependent rail connections; ideal Boolean switching does not establish valid full-swing output levels in every input state. The official marks-to-all decision is therefore preserved instead of forcing the idealized XNOR option as the graded answer.

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