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GATE 2016 EC (EC3) – Question 53

Digital Circuits · Combinatorial Circuits · 2 marks · Multiple choice

The figure gives a five-variable K-map for P,Q,R,S,X. The minimum sum-of-products expression is

Diagram for GATE 2016 EC (EC3) question 53
  1. $\bar P\bar QS\bar X+P\bar QS\bar X+Q\bar R\bar SX+QR\bar SX$
  2. $\bar QS\bar X+Q\bar SX$
  3. $\bar QSX+Q\bar S\bar X$
  4. $\bar QS+Q\bar S$

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Correct answer: (B) $\bar QS\bar X+Q\bar SX$

Explanation

For X=0, the four ones occupy columns Q=0 and rows S=1. P and R vary within that four-cell group, yielding $\bar QS\bar X$.

For X=1, the four ones occupy Q=1 and S=0, with P and R again varying. This group yields $Q\bar SX$.

No corresponding one-cells overlap across the X maps, so X cannot be eliminated. The minimum expression is **$\bar QS\bar X+Q\bar SX$, B**.

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