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GATE 2017 EE (EE2) – Question 39

Electric Circuits · Transient response of DC and AC networks, sinusoidal steady-state analysis, resonance, two port networks, balanced three phase circuits, star-delta transformation, complex power and power factor in AC circuits · 2 marks · Multiple choice

A balanced Y–Y connected three-phase circuit has line-to-line rms voltage 208 V. The load absorbs total power 432 W at power factor 0.6 leading. Its per-phase impedance Z is approximately

Diagram for GATE 2017 EE (EE2) question 39
  1. $33\angle-53.1^\circ\ \Omega$
  2. $60\angle53.1^\circ\ \Omega$
  3. $60\angle-53.1^\circ\ \Omega$
  4. $180\angle-53.1^\circ\ \Omega$

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Show answer and explanation

Correct answer: (C) $60\angle-53.1^\circ\ \Omega$

Explanation

For a star load, $V_{ph}=208/\sqrt3$ V. From $P=3V_{ph}^2\cos\phi/|Z|$, obtain $|Z|=208^2(0.6)/432=60.09$ Ω.

The angle magnitude is arccos(0.6)=53.13°. Leading current means a capacitive, negative impedance angle. Hence **$Z\approx60\angle-53.1^\circ\ \Omega$, C**.

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