A symmetric ±15 V square wave of 50% duty and period 0.4π ms drives series RLC with R=5 Ω,L=10 mH,C=4 μF. Find amplitude in volts of the capacitor-voltage component at 5000 rad/s.
The period gives fundamental ω0=2π/(0.4π ms)=5000 rad/s. The square wave's fundamental peak is 4(15)/π=60/π V.
At that frequency XL=ωL=50 Ω and XC=1/(ωC)=50 Ω, so the series circuit resonates and its impedance is R=5 Ω. Current peak is (60/π)/5=12/π A.
Capacitor-voltage peak is Ipeak XC=600/π=**190.986 V**, within 190–192 V.
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