GATE 2015 EE (EE2) – Question 7
In triangle PQR, PS bisects angle QPR and $\angle QPS=60^\circ$. With PQ=r, PR=q and QR=p as shown, the length PS is

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Correct answer: (B) $qr/(q+r)$
Explanation
The angle at P is twice 60°, namely 120°. The internal-angle-bisector length for adjacent sides q,r and included angle P is $PS=2qr\cos(P/2)/(q+r)$.
Substitute cos60°=1/2 to get **PS=qr/(q+r), B**. The formula follows by the angle-bisector theorem combined with the cosine rule, and has the correct dimension of length.
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