GATE 2015 EE (EE2) – Question 41

Power Electronics · DC to DC conversion: Buck, Boost and Buck-Boost Converters · 2 marks · Numerical answer

The ideal buck converter has fs=100 kHz, duty 0.6, input 60 V, L=5 mH and ripple-free output 36 V. Find load resistance R in ohms for just-continuous inductor current.

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Correct answer: 2480 to 2520

Explanation

At the continuous/discontinuous boundary the minimum inductor current is zero, so average load current equals half the peak-to-peak ripple.

The on-state ripple is ΔI=(Vin−Vo)D/(Lfs)=(60−36)0.6/(0.005×100000)=0.0288 A. Thus Iout=0.0144 A.

The boundary resistance is 36/0.0144=**2500 Ω**, within 2480–2520.

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