For the neutral Ru–Ru complex shown, which bridging L1,L2 combination makes both metals obey the 18-electron rule? Candidate ligands are H⁻, NO⁻, MeCH²⁻ and CO. Ru atomic number is 44.
For the symmetric neutral pair with two Cp⁻ groups and a bridging alkylidene of charge −2, each Ru is formally +2 (d⁶). At each Ru count d⁶ + Cp (6e) + terminal CO (2e) + the shared alkylidene (2e per metal) + bridging CO (1e per metal) + Ru–Ru bond (1e) = 18. Therefore L1 = MeCH²⁻ and L2 = CO, C. Replacing the alkylidene by hydride changes both oxidation-state balance and the donation count.
More Organometallics: 18-Electron rule; metal-alkyl, metal-carbonyl, metal-olefin and metal-carbene complexes and metallocenes. Fluxionality in organometallic complexes. Types of organometallic reactions. Homogeneous catalysis – Hydrogenation, hydroformylation, methanol to acetic acid process, olefin metathesis and Wacker oxidation. Heterogeneous catalysis – Fischer-Tropsch reaction, Ziegler-Natta polymerization. questions
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