Hexapeptide P has pI 6.9. Variant Q replaces glutamate at position 3 with valine. They undergo polyacrylamide-gel electrophoresis at pH 8.0. Which is CORRECT?
Correct answer: (A) P migrates faster than Q toward the anode.
Explanation
At pH above its pI, P is negatively charged and moves toward the positive anode. Removing a glutamate carboxylate in Q makes Q less negative under these conditions. With comparable hexapeptide sizes, P therefore has the larger anodal mobility, A. This is the charge-dependent native electrophoresis interpretation, not SDS-imposed equal charge-to-mass migration.
More Analytical tools: Electrophoresis, microarrays, enzymatic assays, immunoassays, immunoblotting, flow cytometry, whole genome and ChIP sequencing questions
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