Mining Geology, Mine Development and Surveying · Mine Surveying · 2 marks · Numerical answer
A tacheometer has multiplying constant100 and additive constant0; the staff is vertical. From P, Q has readings1.4,2.7,3.9 m and vertical angle7°; R has readings2.1,2.8,3.6 m and angle5°. Q’s RL is102 m. Find R’s RL in m to two decimals.
For vertical staff, height from instrument axis to the central-hair point is V=(Ks/2)sin2θ. At Q,s=2.5, so VQ=125sin14°. Instrument-axis RL is102−VQ+2.7. At R,s=1.5, so VR=75sin10° and R’s RL is102−125sin14°+2.7+75sin10°−2.8≈84.69 m. Central staff readings must be subtracted after each inclined sight.
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