GATE 2023 CE (CE1) – Question 54
An idealised bridge truss is shown in the figure. The force in Member U$_2$L$_3$ is __________________ kN (round off to one decimal place).

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Correct answer: 14.03 to 14.17
Explanation
The total load is $5 \times 20 = 100$ kN, so each support reaction is 50 kN by symmetry. Cut the truss through the panel between U2 and U3 (members U2U3, U2L3 and L2L3). For the left part, the vertical force available is $50 - 20 - 20 = 10$ kN upward (the loads at U1 and U2 are on the left). This must be balanced by the vertical component of the diagonal, which is at 45° (3 m by 3 m): $F\sin 45° = 10$, so $F = 10\sqrt{2} = 14.1$ kN. The diagonal runs downward to the right and pulls on the left part, so it is in tension.