GATE 2024 IN – Question 59
In the circuit shown, assume the opamp is ideal and the initial charge on the capacitor is zero. The output voltage at time t = 2 ms is _____ V (rounded off to one decimal place).
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Correct answer: -2.6 to -2.4
Explanation
The ideal integrator output is $V_o(t)=-(1/RC)\int_0^t V_{in}(\tau)\,d\tau$. Before 2 ms, only the 0–1 ms pulse contributes, with area $5(0.001)=0.005$ V·s. Since $RC=1000(2\times10^{-6})=0.002$ s, $V_o(2\ \mathrm{ms})=-0.005/0.002=\boxed{-2.5}$ V.