GATE 2018 ME (ME1) – Question 23
Taylor tool-life exponent is n = 0.5. If cutting speed is reduced by 50%, new tool life divided by original tool life is ______.
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (A) 4
Explanation
Taylor’s relation is $VT^n=C$. Thus $T_{\mathrm{new}}/T_{\mathrm{old}}=(V_{\mathrm{old}}/V_{\mathrm{new}})^{1/n}=2^2=4$ (A).