GATE 2016 CE (CE1) – Question 48
Two plates are connected by fillet welds of size 10 mm and subjected to tension, as shown in the figure. The thickness of each plate is 12 mm. The yield stress and the ultimate tensile stress of steel are 250 MPa and 410 MPa, respectively. The welding is done in the workshop (γmw = 1.25). As per the Limit State Method of IS 800: 2007, the minimum length (rounded off to the nearest higher multiple of 5 mm) of each weld to transmit a force P equal to 270 kN (factored) is

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Correct answer: (B) 105 mm
Explanation
The weld throat is0.7·10=7mm and design shear strength is410/(sqrt3·1.25)=189.37N/mm². Two equal welds resist270000N, requiring effective length per weld270000/(2·7·189.37)=101.84mm. Choose **105mm, B**, as the listed effective length. If overall weld length were requested, the end allowance would also be needed.